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Jul 16 at 12:57 history protected Carlo Beenakker
Nov 6, 2021 at 17:07 answer added TravorLZH timeline score: 12
S Mar 24, 2019 at 10:47 history suggested Rafael Marazuela CC BY-SA 4.0
I've added a link to the Wikipedia.
Mar 24, 2019 at 9:16 review Suggested edits
S Mar 24, 2019 at 10:47
Mar 23, 2019 at 1:05 comment added Nell @user1729: if I understand correctly, there is even tradeoff between (G)RH computations and the verification you mention in (2): the proof of ternary Goldbach uses a (G)RH check up to a finite height, and had it used a smaller height (presumably still above a certain level), it would have needed a verification up to a higher $n$.
Mar 22, 2019 at 17:24 vote accept Hollis Williams
Mar 21, 2019 at 19:01 comment added Thomas Sauvaget Note also that there is interesting work of Voros arxiv.org/pdf/1703.02844.pdf not directly on Riemann zeros but on modified Keiper-Li sequences that are fully explicit and can capture behaviour of zeros off the critical line (but see the discussion p27 onwards "Now the true current challenge...").
Mar 21, 2019 at 18:14 comment added literature-searcher Zagier famously gave 300 million zeros as the level of experiment needed to convince him, and when computations hit 200 million, the computationalists were cajoled to extend this so that a bet with Bombieri could be won. maths-people.anu.edu.au/~brent/pub/pub081.html
Mar 21, 2019 at 18:05 comment added J Fabian Meier Let me add a different angle: Going through millions of zeros is experimental evidence for the hypothesis. Whether it is stronger or weaker than a possible proof that is probably so complicated that only a dozen people in the world will understand it, is up to you.
Mar 21, 2019 at 17:31 history edited YCor CC BY-SA 4.0
edited tags; edited title
Mar 21, 2019 at 17:04 comment added reuns Note there is some computable $C$ such that $\psi(n) =1_{x > 1} \log \lfloor \exp(n-\sum_{|\Im(\rho)| < Cn} \frac{(n+1/2)^\rho}{\rho})+\frac12(1- \log 2\pi-\log(1-(n+1/2)^{-2}))\rfloor $. The RH aims at replacing $Cn$ by $C' n^{1/2} \log^3 n$. From the small non-trivial zeros you know $\psi(n)$ for $n$ small, and from $\psi(n)$ for $n$ small and the knowledge that the RH is true for $\Im(s)$ small, you know the approximate imaginary part of the non-trivial zeros.
Mar 21, 2019 at 16:14 answer added user1728 timeline score: 50
Mar 21, 2019 at 16:02 comment added Hollis Williams Yes, I am familiar with the work Turing did with his computers to see if he could find a counterexample: I suppose the modern work with supercomputers could be viewed as an extension of that research.
Mar 21, 2019 at 15:48 history became hot network question
Mar 21, 2019 at 15:39 answer added Conrad timeline score: 27
Mar 21, 2019 at 15:20 comment added Richard Stanley The Riemann hypothesis may be false. Even if one feels that the chance that RH is false is very small, the expected payoff for finding a counterexample is still large.
Mar 21, 2019 at 14:26 comment added user1729 Regarding your last paragraph: The proof of the Ternary Goldbach Conjecture proceeded in two steps: 1) prove the result for all numbers bigger than a certain, known number $n$, and 2) use a computer to verify the result for all numbers less than $n$. It is conceivable that a similar method of proof would work for the Riemann hypothesis.
Mar 21, 2019 at 14:24 comment added Nell Is there really such a huge amount of (human) work on numerical verifications? I am not aware of that many papers.
Mar 21, 2019 at 14:16 answer added Nell timeline score: 25
Mar 21, 2019 at 13:52 history asked Hollis Williams CC BY-SA 4.0