Timeline for Do analytic functionals form a cosheaf?
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Apr 23, 2019 at 13:50 | comment | added | Daniel Bruegmann | What do you mean by "completely symmetric duality" and how do you intend to apply this here? In particular, it is not true in general that (ker f)' is isomorphic to coker (f') if f is a continuous homomorphism which is not strict. | |
| Mar 21, 2019 at 15:43 | comment | added | user131781 | I should add the proviso that I was tacitly assuming that we are dealing with open subsets of $n$-dimensional complex spaces. As pointed out above, the case of a general complex manifold could involve some subtle problems. | |
| Mar 21, 2019 at 11:00 | history | answered | user131781 | CC BY-SA 4.0 |