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May 1, 2020 at 4:45 comment added Ian Agol By the way, the analogous question for $SL_n(\mathbb{Z})$, $n > 2$ follows from Margulis' superrigidity theorem. en.wikipedia.org/wiki/Superrigidity To clarify, do you want a characterization of when the representation is induced by a representation of $SL(2,\mathbb{C})$ for the standard embedding induced by $\mathbb{Z}\subset \mathbb{C}$? Or are other representations of $SL(2,\mathbb{Z})\to SL(2,\mathbb{C})$ allowed?
Apr 13, 2019 at 6:10 comment added Venkataramana One "intrinsic" condition is that the Zariski closure in $GL_N(\mathbb C)$ iof the image of $SL(2,\mathbb Z)$ is $SL(2,\mathbb C)$ or $PGL(2,\mathbb C)$..
Mar 20, 2019 at 22:00 comment added Nate Indeed, and you can note I clarified that $E_{1,2}(1)$ acts unipotently.
Mar 20, 2019 at 21:48 comment added YCor This is because usually $e_{ij}(x)$ is called elementary for arbitrary $x$, and then they're not conjugate in $SL_2(Z)$. For instance in $SL_2(Z)$, $e_{12}(1)$ and $e_{12}(2)$ are not conjugate. So the condition that the second one is mapped to a unipotent element doesn't imply that the first is mapped to a unipotent element.
Mar 20, 2019 at 20:02 history edited Nate CC BY-SA 4.0
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Mar 20, 2019 at 20:02 comment added Nate Well by "elementary matrix" I meant the identity matrix with a single extra 1 somewhere off the diagonal. They are all conjugate, so there is no difference. I will try to clarify.
Mar 20, 2019 at 19:53 comment added YCor "iff an elementary matrix acts unipotently": you mean "every" elementary matrix?
Mar 20, 2019 at 19:51 comment added Nate Yes, finite dimensional ones.
Mar 20, 2019 at 19:48 comment added YCor What kind of representations are you looking at? finite-dimensional ones?
Mar 20, 2019 at 19:20 history asked Nate CC BY-SA 4.0