Skip to main content
17 events
when toggle format what by license comment
S Apr 1, 2019 at 9:01 history bounty ended CommunityBot
S Apr 1, 2019 at 9:01 history notice removed CommunityBot
Mar 24, 2019 at 8:50 vote accept James Baxter
Mar 24, 2019 at 8:47 answer added Taras Banakh timeline score: 7
S Mar 24, 2019 at 7:33 history bounty started James Baxter
S Mar 24, 2019 at 7:33 history notice added James Baxter Draw attention
Mar 22, 2019 at 6:55 comment added James Baxter Also, I’ve modified the question a little.
Mar 22, 2019 at 6:55 history edited James Baxter CC BY-SA 4.0
added 36 characters in body
Mar 22, 2019 at 6:51 comment added James Baxter This function is discontinuous everywhere with oscillation 1, so the integral would be 1 as well.
Mar 22, 2019 at 1:53 comment added Gary Moon I hate to ask a question so similar to one that was just answered, but I feel that I'm still missing something here (probably just one of those days :) ). If we took $f=\chi_{\mathbb{Q}\cap [0,1]}$, what would we get for $O(f,e)$?
Mar 21, 2019 at 19:07 history edited James Baxter CC BY-SA 4.0
deleted 14 characters in body
S Mar 20, 2019 at 19:41 history suggested Daniele Tampieri CC BY-SA 4.0
Tried to render the formula defining O(f,e) in a better way using \substack LaTEX command
Mar 20, 2019 at 19:40 review Suggested edits
S Mar 20, 2019 at 19:41
Mar 20, 2019 at 12:47 comment added James Baxter This would be zero for all e, since for any such H with m(H) = e, we have that the oscillation on H is 0 a.e. (everywhere except 0 and 1/2). So the integral is 0.
Mar 20, 2019 at 12:01 comment added Fedor Petrov I am not sure that I understood the definition, what is $O(f,e)$ for $f=\chi_{(0,1/2]}$?
Mar 20, 2019 at 8:57 comment added Dave L Renfro Possibly Jack Brown's 1995 survey paper Restriction theorems in real analysis (preprint version here) could be of use, at least in pointing you to possibly relevant literature.
Mar 20, 2019 at 7:26 history asked James Baxter CC BY-SA 4.0