Timeline for Asympotic density of a very simple sequence
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 19, 2019 at 21:10 | vote | accept | Yaakov Baruch | ||
| Mar 19, 2019 at 21:10 | comment | added | Yaakov Baruch | Notice that $\frac{\Gamma^2(1/3)}{4\Gamma(2/3)}$ is exactly half of my estimate with multiplicities, which is $2.6499581...×C^{2/3}$. This means that the multiplicity of a number is on average $1$ (aside from switching $m$ and $n$). | |
| Mar 19, 2019 at 20:47 | history | answered | Stanley Yao Xiao | CC BY-SA 4.0 |