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Mar 21, 2019 at 3:58 comment added Nik Weaver Yes, it's obvious. Take $A$ to be the matrix with a $1$ in the $(1,1)$ entry and $0$'s everywhere else.
Mar 21, 2019 at 1:10 review Reopen votes
Mar 21, 2019 at 5:26
Mar 21, 2019 at 0:51 history edited Alex Wenxin Xu CC BY-SA 4.0
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Mar 21, 2019 at 0:50 comment added Alex Wenxin Xu sorry I meant whether the left-hand side is tight up to universal constant? Is that also obvious?
Mar 19, 2019 at 21:40 history closed Alexandre Eremenko
Sean Lawton
user44191
Piotr Hajlasz
David Handelman
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Mar 19, 2019 at 12:15 review Close votes
Mar 19, 2019 at 21:40
Mar 19, 2019 at 11:57 comment added Alexandre Eremenko Yes, it is tight: take $A=I$, for example.
S Mar 19, 2019 at 7:52 history edited R.P. CC BY-SA 4.0
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S Mar 19, 2019 at 7:52 history suggested M. Winter CC BY-SA 4.0
Added MathJax in title
Mar 19, 2019 at 7:50 review Suggested edits
S Mar 19, 2019 at 7:52
Mar 19, 2019 at 7:42 answer added InfiniteLooper timeline score: 1
Mar 19, 2019 at 7:19 history asked Alex Wenxin Xu CC BY-SA 4.0