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S Dec 23, 2023 at 2:03 vote accept Colin McLarty
Dec 22, 2023 at 0:09 comment added David Roberts Colin - did you see the update to the answer?
Nov 26, 2021 at 21:35 answer added Elliot Glazer timeline score: 15
Mar 21, 2019 at 16:09 vote accept Colin McLarty
S Dec 23, 2023 at 2:03
Mar 20, 2019 at 23:30 review Close votes
Mar 21, 2019 at 9:58
Mar 20, 2019 at 15:52 comment added Colin McLarty @JohannesSchürz Yes, I believe Gaifman's proof is essentially the same. He just uses the fact that ZFC proves existence of enough partial well-orderings of the universe, that you do not really need forcing.
Mar 20, 2019 at 15:19 comment added Johannes Schürz The proof by Felgner is not hard: take a model of ZFC and define a (proper class) forcing consisting of 'all partial well-orderings of the universe'. This forcing will add no new sets, but (by genericity) G will be a global well-ordering. Furthermore, Replacement with respect to G holds due to the Forcing Theorem (which holds for this particular class forcing)
Mar 20, 2019 at 8:52 answer added Ali Enayat timeline score: 16
Mar 19, 2019 at 12:28 history edited Martin Sleziak CC BY-SA 4.0
added eudml link
Mar 19, 2019 at 11:34 comment added David Roberts thanks, that makes more sense.
Mar 19, 2019 at 11:26 comment added Colin McLarty @DavidRoberts Sorry, that "replacement" was a typo for "separation." Corrected.
Mar 19, 2019 at 11:25 history edited Colin McLarty CC BY-SA 4.0
deleted 1 character in body
Mar 19, 2019 at 7:23 review Suggested edits
Mar 19, 2019 at 8:35
Mar 19, 2019 at 6:57 comment added David Roberts Do you mean ZF+Global Choice, since you are referring to Replacement at the end of your first paragraph. Or do you mean Z+Global Choice, and Separation can refer to the choice function $F$?
Mar 19, 2019 at 5:06 review Suggested edits
Mar 19, 2019 at 6:56
Mar 19, 2019 at 4:35 history edited Colin McLarty CC BY-SA 4.0
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Mar 19, 2019 at 3:10 history asked Colin McLarty CC BY-SA 4.0