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Mar 22, 2019 at 15:41 history edited esg CC BY-SA 4.0
Corrected a mistake
Mar 22, 2019 at 15:37 comment added esg Yes, you are right. Apologies for being sloppy. I'll correct it.
Mar 22, 2019 at 12:51 comment added Mare I think I found a small mistake in your remark (1). Namely we have $det(Z)=(-1)^{n-1}$ so the final equivalent reformulation should be: For which $\mathbf{v}$ is $\det(M_\mathbf{v})=(-1)^{(w-1)(n-1)}$?
Mar 20, 2019 at 19:38 comment added esg I have just corrected a sign, but nothing essential has changed. The structure of the formula is easy to explain, but I don't see why only the factors +1 and -1 appear. If I don't have a new idea tomorrow I'll post the conjecture.
Mar 20, 2019 at 19:30 history edited esg CC BY-SA 4.0
corrected sign
Mar 19, 2019 at 18:47 comment added Mare It would feel a little weird to post your conjecture. So it is probably better when you post it ;)
Mar 19, 2019 at 18:04 comment added esg You're welcome. Yes, I think it will get more attention with the tags "linear algebra" and "determinants". Feel free to post it - in a sense it is your conjecture (as follow-up of this post).
Mar 19, 2019 at 12:47 comment added Mare Thank you, that looks very interesting. Maybe it would be a good idea to post the conjecture in a new thread, since here it likely wont get much attention?
Mar 17, 2019 at 18:50 history answered esg CC BY-SA 4.0