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Mar 16, 2019 at 18:02 comment added zhoraster For a fixed $n$, consider such distribution: $P(X_1 = n) = 1-P(X_1=0) < 1/n$. Then $EX_1<1$ and for $k=1,\dots,n$ the probability $P(S_k >k) = P(\exists i\le k: X_i = n)$ is obviously increasing in $k$.
Mar 16, 2019 at 11:47 comment added kodlu Interesting. Could you elaborate.
Mar 16, 2019 at 11:16 comment added zhoraster Of course, it is not necessary: one can construct many examples of distributions which satisfy this property, but don't have a non-decreasing density (or even have no density at all). But some assumption is certainly needed. Actually, for each $n$ it is possible to construct a distribution such that $P(S_n > cn) > P(S_{n-1}>c(n-1)) >\dots >P(X_1>c)$ for some $c>EX_1$.
Mar 14, 2019 at 10:23 history asked kodlu CC BY-SA 4.0