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Mar 14, 2019 at 13:26 vote accept Bruno
Mar 14, 2019 at 9:37 comment added Bruno @Dap yeah, I agree with the use of Dirac measure. So, we cannot talk about the convergence in all Borel measure.
S Mar 14, 2019 at 9:07 history suggested user64494 CC BY-SA 4.0
A typo (missed ?) in the title is corrected and the title is refined
Mar 14, 2019 at 7:07 comment added Dap Similar question: math.stackexchange.com/questions/2482042/…
Mar 14, 2019 at 6:40 review Suggested edits
S Mar 14, 2019 at 9:07
Mar 14, 2019 at 0:01 comment added Nate Eldredge @ChristianRemling: And moreover, the dual of $L^\infty$ is only those finitely additive set functions which are absolutely continuous to your reference measure (which has not been specified). I think this question needs to be clarified.
Mar 13, 2019 at 17:14 comment added Christian Remling I don't think this is weak convergence, the dual of $L^{\infty}$ is finitely additive set functions, not just measures.
Mar 13, 2019 at 12:16 answer added Robert Israel timeline score: 6
Mar 13, 2019 at 11:40 review First posts
Mar 13, 2019 at 12:57
Mar 13, 2019 at 11:39 history asked Bruno CC BY-SA 4.0