Timeline for Accessible functors not preserving lots of presentable objects
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Mar 13, 2019 at 13:09 | vote | accept | Mike Shulman | ||
Mar 13, 2019 at 13:03 | comment | added | Mike Shulman | @Denis-CharlesCisinski As far as I know that is only true if you either remove the $\lambda$-filteredness condition on the colimits (see Remark 1.30 in AR) or add the assumption that $\lambda\lhd\mu$ (which changes it from "for sufficiently large $\mu$" to "for arbitrarily large $\mu$" -- see Remark 2.15 in AR). | |
Mar 13, 2019 at 8:47 | history | became hot network question | |||
Mar 13, 2019 at 7:50 | answer | added | Jiří Rosický | timeline score: 13 | |
Mar 13, 2019 at 7:26 | comment | added | D.-C. Cisinski | We may assume that $F$ preserves small $\lambda$-filtered colimits. Isn’t it true that, for $\mu$ large enough, an object is $\mu$-presentable if and only if it is a $\mu$-small $\lambda$-filtered colimit of $\lambda$-presentable objects? Another way to put it, is that for $\mu$ large enough (e.g. larger than $\lambda$ and than the set of maps between any two $\lambda$-presentable objects), the property of $\mu$-presentability of an object $X$ is simply the fact that the set of maps from a $\lambda$-presentable object to $X$ is of cardinal $\leq\mu$. | |
Mar 13, 2019 at 5:17 | comment | added | Reid Barton | For fixed $\alpha$, does $\mu^\alpha = \mu$ hold for all sufficiently large regular $\mu$? | |
Mar 13, 2019 at 2:25 | history | asked | Mike Shulman | CC BY-SA 4.0 |