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Mar 19, 2019 at 19:14 vote accept A.Garcia
Mar 19, 2019 at 13:17 history edited Libli CC BY-SA 4.0
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Mar 19, 2019 at 11:18 comment added Libli @A.Garcia You are right, I made a mistake in the description of orbits. I will edit.
Mar 19, 2019 at 11:16 history edited Libli CC BY-SA 4.0
Mistakes in the description of orbits
Mar 19, 2019 at 6:16 comment added A.Garcia I agree that $E_6\times \mathbb G_m$ does not act on trace zero matrices, that was my mistake.
Mar 19, 2019 at 6:15 comment added A.Garcia I am sorry but I am very confused. The book Algebraic Geometry of Parshin Shafarevich et al says that the representation of F4 on the trace zero hyperplane has a 2-dimensional rational quotient. How can this reconcile with what you say?
Mar 18, 2019 at 18:20 comment added A.Garcia I think there is a mistake. Are you doing $E_6\times \mathbb G_m$?
Mar 13, 2019 at 16:27 comment added Victor Petrov If the base field is not closed, iv) becomes a union of orbits according to $N(x)\bmod (F^*)^3$, where $N$ is the norm.
Mar 12, 2019 at 22:04 history answered Libli CC BY-SA 4.0