Timeline for How did Cole factor $2^{67}-1$ in 1903?
Current License: CC BY-SA 4.0
8 events
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| Apr 1, 2023 at 8:32 | history | edited | Federico Poloni | CC BY-SA 4.0 |
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| Mar 20, 2019 at 19:33 | history | edited | Federico Poloni | CC BY-SA 4.0 |
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| Mar 20, 2019 at 19:28 | comment | added | Federico Poloni | @MarkS Yes! I have expanded my answer with a description of the division process. I hope it is sufficiently understandable. | |
| Mar 20, 2019 at 19:26 | history | edited | Federico Poloni | CC BY-SA 4.0 |
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| Mar 20, 2019 at 19:11 | comment | added | Mark S | That's a pretty nifty looking piece of kit. I don't think Cole was looking for two candidate factors that, when multiplied, equal $2^{67}-1$, but rather he was looking for one candidate factor that, when divided into $2^{67}-1$ left a remainder of $0$. Arithmometers sound like they can handle big division problems as well as big multiplication problems. | |
| Mar 11, 2019 at 7:29 | history | edited | Federico Poloni | CC BY-SA 4.0 |
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| Mar 10, 2019 at 23:25 | history | edited | Federico Poloni | CC BY-SA 4.0 |
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| Mar 10, 2019 at 23:14 | history | answered | Federico Poloni | CC BY-SA 4.0 |