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Jun 14, 2019 at 19:05 comment added Per Alexandersson @Marcel: Ah you are right of course! Hm, so there is a nice relationship using $\omega$ between orthogonal and symplectic Schur, so if there is a Murnaghan-Nakayama rule for one of these, then there is one for the other.
Jun 14, 2019 at 17:46 comment added Marcel Exactly, so the function $o_\lambda(x)$ has $2n$ arguments and has full $S_{2n}$ symmetry with respect to them, yes? So why did you suggest in your answer to treat the positive and negative alphabets separately?
Jun 14, 2019 at 17:42 comment added Per Alexandersson @Marcel : ah, i should add a warning - on the top of the page, it is stated what the alphabet is, (which includes the negative powers!).
Jun 14, 2019 at 17:14 comment added Marcel Wait, the formula you give for $o_\lambda$ in your page as a determinant of a difference of $h$-functions is symmetric in all its arguments. I don't understand.
Mar 7, 2019 at 23:51 vote accept Marcel
Mar 7, 2019 at 9:57 history answered Per Alexandersson CC BY-SA 4.0