Timeline for When is $\sum_{n\in\mathbb Z} f(x+n)$ constant?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 11, 2019 at 8:16 | comment | added | YCor | What's precisely assumed on $f$? that $f$ is analytic, and that there exists a constant $c=c(f)$ such that for every $x$, the sum $\sum_{k=-n}^nf(x+n)$ converges to $c$? it's not obvious for me that a non-absolutely convergent sum over $\mathbf{Z}$ should be evaluated only on symmetric intervals, so I'm not sure what's meant. | |
| Mar 11, 2019 at 5:16 | answer | added | u136536 | timeline score: -2 | |
| Mar 7, 2019 at 8:53 | comment | added | InfiniteLooper | Or take any translate of it. | |
| Mar 6, 2019 at 20:22 | vote | accept | W-t-P | ||
| Mar 6, 2019 at 19:56 | answer | added | Carlo Beenakker | timeline score: 34 | |
| Mar 6, 2019 at 19:56 | comment | added | Christian Remling | You can presumably just take derivatives of that identity to produce lots of other functions (I didn't carefully check how to justify this though). | |
| Mar 6, 2019 at 19:45 | history | asked | W-t-P | CC BY-SA 4.0 |