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Jun 15, 2020 at 7:27 history edited CommunityBot
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Mar 6, 2019 at 21:59 history edited Francesco Polizzi CC BY-SA 4.0
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Mar 6, 2019 at 14:38 comment added Francesco Polizzi @DonuArapura: you are right, thanks for the observation. I was actually talking about a counterexample to the theorem in my answer.
Mar 6, 2019 at 13:01 comment added Donu Arapura Francesco, just to clarify, Raynaud gives an example where $\mathcal{L}$ is ample but $H^1(X, \mathcal{L}^{-1})\not=0$. It is possible that the actual question, where $q=0$, might be OK.
Mar 6, 2019 at 9:10 history edited Francesco Polizzi CC BY-SA 4.0
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Mar 6, 2019 at 9:05 history answered Francesco Polizzi CC BY-SA 4.0