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Mar 4, 2019 at 15:54 comment added Sándor Kovács There is also an interesting computation of the Kodaira dimension of a singular variety on Terry Tao's blog: terrytao.wordpress.com/2014/12/20/…, see also the last comment for a more AG way of the same: terrytao.wordpress.com/2014/12/20/…
Mar 4, 2019 at 15:54 comment added Sándor Kovács As long as your varieties have canonical singularities you can compute the Kodaira dimension the same way as in the smooth case. For the definition of the canonical sheaf/divisor see mathoverflow.net/questions/35736/….
Mar 2, 2019 at 16:55 review Close votes
Mar 7, 2019 at 3:05
Mar 2, 2019 at 16:26 comment added Will Sawin One just defines the Kodaira dimension as the dimension of a resolution of singularities, because it is known to be birationally invariant, so it does not depend on a choice of resolution. The answer obviously depends a lot on the type of singularities, since every variety is birational to a hypersurface. But I'm sure there are nice formulas in many interesting special cases...
Mar 2, 2019 at 16:21 history asked user221330 CC BY-SA 4.0