Timeline for Can a hyperbolic manifold be a product?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 1 at 1:57 | comment | added | Michael Albanese | Some more examples of products which admit a complete hyperbolic metric are constructed in this answer. | |
| May 23, 2022 at 22:42 | vote | accept | Michael Albanese | ||
| Feb 27, 2019 at 18:45 | history | edited | YCor |
edited tags
|
|
| Feb 27, 2019 at 18:44 | answer | added | YCor | timeline score: 9 | |
| Feb 27, 2019 at 18:18 | comment | added | YCor | The answer to Question 2 is a trivial "yes" for every $n\ge 2$. | |
| Feb 27, 2019 at 18:17 | comment | added | YCor | I don't think you want to call the positive isometry group $O^+(n,1)$, because the action of $SO(n,1)$ is not faithful when $n$ is odd; rather $PO_0(n,1)$. Anyway, this does not matters so much for the question. | |
| Feb 27, 2019 at 18:03 | comment | added | Danny Ruberman | For question 1, take two commuting parabolic elements that generate a discrete subgroup. Then the quotient (say in dimension 3) is diffeomorphic to $T^2 \times R = (S^1 \times R) \times S^1$. Is that what you're asking for? | |
| Feb 27, 2019 at 17:51 | history | asked | Michael Albanese | CC BY-SA 4.0 |