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Feb 24, 2019 at 12:47 vote accept Dominic van der Zypen
Feb 24, 2019 at 9:21 comment added Martin Sleziak Only after posting the answer below I have noticed this older post: Space $X$ such that $X^\lambda\cong X$ for some $\lambda$. Is the only difference between the two posts that in the older one you allow also infinite cardinals and here only integers?
Feb 24, 2019 at 8:34 answer added Martin Sleziak timeline score: 6
Feb 24, 2019 at 7:59 history asked Dominic van der Zypen CC BY-SA 4.0