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Feb 25, 2019 at 0:09 vote accept dorebell
Feb 25, 2019 at 0:07 comment added dorebell Yes, I think both of those adjustments are right. Thanks for the reference! I'm surprised by the simplicity of the argument - it looks like Katz essentially just writes down a solution directly as a "matrix exponential". The condition of being $(t_1, \ldots, t_n)$-adically continuous should say exactly that the integrable connection is specified by differential equations $\frac{\partial}{\partial t_k} s = \sum_j M^j_{ik} s$, right? (i.e. some random integrable connection on the power series ring might not land in the span of the $dt_i$'s.)
Feb 24, 2019 at 17:58 comment added Avi Steiner Nice answer! I want to emphasize that this proposition is really saying that integrable connections are only really interesting as global objects---locally, they're all determined up to isomorphism by their rank.
Feb 24, 2019 at 2:35 review First posts
Feb 24, 2019 at 3:03
Feb 24, 2019 at 2:34 history answered user136220 CC BY-SA 4.0