Skip to main content
added 16 characters in body
Source Link

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic number sequence because it clearly has properties related to both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$$$\Theta_0 = 1\mid\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic number sequence because it clearly has properties related to both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic number sequence because it clearly has properties related to both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_0 = 1\mid\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

added 12 characters in body
Source Link

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic numbersnumber sequence because theyit clearly havehas properties ofrelated to both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic numbers because they clearly have properties of both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic number sequence because it clearly has properties related to both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

Tried to make it more coherent.
Source Link

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic numbers because they clearly have properties of both triangular and harmonic numbers. The

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is

$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2}$$
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic numbers because they clearly have properties of both triangular and harmonic numbers. The simplest closed form of the sequence is

$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2}$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

I have decided to call this sequence $\Theta_n$ for the triangular-harmonic numbers because they clearly have properties of both triangular and harmonic numbers.

I had been studying it by using the recursive definition $$\Theta_n = \Theta_{n-1} + \frac{1}{\lfloor\Theta_{n-1}\rfloor}$$ The simplest closed form of the sequence is
$$\Theta_n = \frac{T_n^{-1}}{2} + \frac{n}{T_n^{-1}} + \frac{1}{2} \mid n\geq1$$ with $$T_n^{-1}=\lfloor\sqrt{2n}+\frac{1}{2}\rfloor$$ being the inverse triangular number function. I have been researching its many fascinating properties.

added 13 characters in body
Source Link
Loading
added 13 characters in body
Source Link
Loading
Source Link
Loading