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Feb 23, 2019 at 15:30 vote accept hookah
Feb 22, 2019 at 21:48 answer added Fedor Petrov timeline score: 2
Feb 22, 2019 at 19:18 comment added Greg Martin Possible strategy: (1) for a typical prime $p$, most arithmetic progressions modulo $p$ contain only integers $n$ for which $p\nmid f(n)$; (2) most integers in any such arithmetic progression have the property that $p$ divides the order of $a$ modulo $n$. Then an ad-hoc density bound, or indeed the large sieve, should give a nontrivial upper bound on the density of $S$. There should be some examples in the literature about integers $n$ for which $n \mid (a^n-1)$.
Feb 22, 2019 at 18:24 history asked hookah CC BY-SA 4.0