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Feb 21, 2019 at 17:12 comment added user48958 You're right, it's $|z|^2$ in the Poincare-Lelong formula.
Feb 21, 2019 at 17:11 history edited user48958 CC BY-SA 4.0
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Feb 21, 2019 at 14:54 vote accept user135826
Feb 21, 2019 at 12:28 comment added user135826 Thanks a lot! Do you mean $\lvert z\rvert^2$ in the definition of $f_{\epsilon}$?
Feb 21, 2019 at 10:30 history answered user48958 CC BY-SA 4.0