Timeline for Is every Lie subgroup of a Lie group isometric to all its conjugates?
Current License: CC BY-SA 4.0
8 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Feb 24, 2019 at 21:06 | vote | accept | Ali Taghavi | ||
Feb 22, 2019 at 12:29 | answer | added | emiliocba | timeline score: 3 | |
Feb 22, 2019 at 10:09 | comment | added | YCor | @AndySanders Of course, bi-invariant is sufficient but not necessary. For instance it's obviously true when $N$ has dimension $1$, or when $N$ is normal. In particular, for $G$ non-abelian of dimension 2, it's true for all $N$. | |
Feb 21, 2019 at 23:30 | comment | added | Francois Ziegler | @AndySanders Not necessarily, as they can be isometric via some map other than $\operatorname{Ad}_g:n\mapsto gng^{-1}$. (E.g. the identity, when $N=G$.) | |
Feb 21, 2019 at 21:38 | comment | added | Andy Sanders | It seems you would want a bi-invariant metric for this to be true... | |
Feb 21, 2019 at 20:52 | answer | added | Francois Ziegler | timeline score: 7 | |
Feb 21, 2019 at 10:25 | history | edited | Ali Taghavi | CC BY-SA 4.0 |
added 24 characters in body
|
Feb 21, 2019 at 9:52 | history | asked | Ali Taghavi | CC BY-SA 4.0 |