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Feb 19, 2019 at 23:46 comment added Nick L I guess that, if there exists a complex structure on $S^{6}$ then there is a natural connect sum operation for complex $3$-folds. This is definitely true in the almost complex category (see exercise 7.28 of "Introduction to symplectic topology" McDuff and Salamon), I would guess that the same idea would work if $S^{6}$ has a complex structure.
Feb 19, 2019 at 23:13 comment added Overflowian Recurring/useful to understanding the topology or complex structure of various class of manifolds. For example with the connected sum and just 3 models we can form all the compact (smooth) manifolds of (real) dimension 2. The question is of course deliberately vague.
Feb 19, 2019 at 23:12 history edited Overflowian CC BY-SA 4.0
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Feb 19, 2019 at 22:53 comment added Francesco Polizzi What do you mean by "most powerful"? I mean, direct product (for instance) makes perfect sense for complex manifolds.
Feb 19, 2019 at 22:36 history asked Overflowian CC BY-SA 4.0