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Feb 20, 2019 at 11:20 vote accept user534666
Feb 20, 2019 at 11:20 history edited user534666 CC BY-SA 4.0
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Feb 19, 2019 at 15:38 comment added Skeeve @user534666 Should $|f^*(x)|=1$ read as $|f(x)|=1$?
Feb 19, 2019 at 11:31 answer added Mateusz Wasilewski timeline score: 2
Feb 19, 2019 at 11:22 comment added Dirk Werner The condition is reasonable; e.g., the constant-1 function in $C[0,1]$ is such an $x$ (and it is extreme). Note that the set of all vectors satisfying the condition in the question is closed; so the best one can hope for is that $x$ is in the (norm-) closure of $E_X$.
Feb 19, 2019 at 11:09 comment added user534666 @erz this question is in context to the proof of Proposition 2 inthis paper sciencedirect.com/science/article/pii/S0022247X03005961 I am not understanding how they make the statement. ‘In particular, $Tx$ is in $E_Y$.
Feb 19, 2019 at 11:03 comment added erz Something is wrong with your condition: $x$ cannot be "parallel" to every extreme point of $E_{X^{*}}$.
Feb 19, 2019 at 10:32 history asked user534666 CC BY-SA 4.0