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Feb 5, 2020 at 13:54 comment added Saal Hardali In this generality it is certainly false. Let $C$ be the coaugmented counital coalgebra over $\mathbb{Q}$ cogenerated by a single primitive cogenerator in (homological) degree $3$. Then $\pi_{\ast} (Comod_C(\mathbb{Q})) = \mathbb{Q}[x]$ with $|x| = 2$ so $\mathbb{Q}$ can't be compact because then $\mathbb{Q}[x^{-1}] = 0$ contradicting that $\pi_{\ast} (End_C(\mathbb{Q}))[x^{-1}] = \mathbb{Q}[x,x^{-1}] \ne 0$
Feb 13, 2019 at 9:16 comment added Saal Hardali Aha, this is the one I know how to make sense of in this generality. Notice however that there are other useful variants which do not always agree see arxiv.org/abs/0905.2621
Feb 13, 2019 at 9:00 comment added Gal Dor Opposite category of the category of modules in the opposite category of $\mathcal{C}$.
Feb 13, 2019 at 8:32 comment added Saal Hardali Probably a stupid question but what definition of the $\infty$ category of comodules are you using?
Feb 13, 2019 at 8:15 history asked Gal Dor CC BY-SA 4.0