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Feb 14, 2019 at 10:30 comment added Asaf Karagila Well, this is very nice. I'm surprised that we don't have the machinery to prove something like $\mathsf{AD}^{L(\Bbb R)}$ from these hypotheses, seeing how we do get $\sf PD$.
Feb 14, 2019 at 4:02 comment added Mohammad Golshani Yes. In fact in the paper, Theorem 3.24 they show that there is a sharp for a model with a strong cardinal.
Feb 13, 2019 at 12:29 comment added Asaf Karagila What do overlapping extenders give us? If my memory serves me right, certain level of strongness?
Feb 13, 2019 at 4:07 history answered Mohammad Golshani CC BY-SA 4.0