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Aug 9, 2021 at 20:05 history edited Emily CC BY-SA 4.0
typos
Mar 9, 2019 at 21:26 history edited Emily CC BY-SA 4.0
Trivial edit: changed phrasing
Feb 9, 2019 at 14:15 history edited Emily CC BY-SA 4.0
formatting
Feb 9, 2019 at 3:34 vote accept Emily
Feb 9, 2019 at 3:34 comment added Emily @DylanWilson Thank you very much for the great pointers! (I have deleted the footnote.)
Feb 9, 2019 at 3:34 history edited Emily CC BY-SA 4.0
Deleted footnote and corrected a typo
Feb 9, 2019 at 3:00 answer added Peter May timeline score: 20
Feb 9, 2019 at 2:42 comment added Dylan Wilson Some references: 4b) follows from the universal properties: $\mathsf{Spaces}_*$ is the unit object in the symmetric monoidal $\infty$-category of presentable pointed $\infty$-categories, and $\mathsf{Sp}$ is a pointed, presentably symmetric monoidal $\infty$-category so the essentially unique colimit-preserving functor from $\mathsf{Spaces}_*$ determined by $S^0$ has an essentially unique refinement to a symmetric monoidal functor. (cf. HA.4.8.2). 4a) right adjoints to symmetric monoidal functors are automatically lax monoidal (HA.7.3.2.7). And 5) can be proven directly or use HA.6.1.1.28
Feb 9, 2019 at 2:24 comment added Dylan Wilson Yes of course. $\Sigma^{\infty}$ is symmetric monoidal, $\Omega^{\infty}$ is lax symmetric monoidal, and $\Omega^{\infty}\Sigma^{\infty}X$ is equivalent to $\mathrm{colim} \Omega^n\Sigma^nX$. Also your footnote "2" is incorrect- the loops-infinity suspension-infinity adjunction is just an adjunction, not an equivalence.
Feb 8, 2019 at 23:10 history asked Emily CC BY-SA 4.0