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Feb 7, 2019 at 12:29 vote accept Alex Meiburg
Feb 7, 2019 at 11:42 answer added LeechLattice timeline score: 8
Feb 7, 2019 at 11:35 history edited Alex Meiburg CC BY-SA 4.0
at least one non-integer eigenvalue
Feb 7, 2019 at 11:34 comment added Alex Meiburg Yes, my mistake. I will clarify in the title.
Feb 7, 2019 at 11:26 comment added Wojowu A graph with all eigenvalues integral will satisfy this vacuously. I presume you want to assume at least one eigenvalue is irrational?
Feb 7, 2019 at 11:23 history asked Alex Meiburg CC BY-SA 4.0