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Feb 7, 2019 at 10:53 comment added Ivan Di Liberti Thanks! Accepted.
Feb 7, 2019 at 10:53 vote accept Ivan Di Liberti
Feb 7, 2019 at 10:52 comment added Yonatan Harpaz @IvanDiLiberti, Note that for every $n$ we have ${\rm Pro}([n]) \simeq [n]$, but there is a non-constant object in ${\rm Pro}([\omega])$, namely, the inverse system given by the identity diagram $\omega \to \omega$ (and which corresponds to the terminal left exact functor sending everything to the point).
Feb 7, 2019 at 10:01 comment added Ivan Di Liberti Thanks for your answer! I completely believe it, because I dot expect the Ind-completion to be an accessible KZ-doctrine over Cat, but is there an evident argument that proves $\text{colim} \text{Pro}([n]) \not \cong \text{Pro}([\omega])$?
Feb 6, 2019 at 22:07 history answered Yonatan Harpaz CC BY-SA 4.0