Skip to main content
5 events
when toggle format what by license comment
Feb 6, 2019 at 22:05 comment added R W On each ergodic component the transition probabilities are constant and coincide with the conditional measure of $\mathbb P$ on this component
Feb 6, 2019 at 21:53 comment added aduh Ah I see, I was forgetting that $\mathbb P$ is assumed to be ergodic in that statement. I still don't see how the last step works though. How does the ergodic decomposition lead to (3)?
Feb 6, 2019 at 21:46 comment added R W Yes - precisely
Feb 6, 2019 at 21:45 comment added aduh Sorry, but I'm not following this. By "almost all transition probabilities coincide with $\mathbb P$" do you mean $P(\cdot, \omega) = \mathbb P$ a.e. $\omega$?
Feb 6, 2019 at 21:15 history answered R W CC BY-SA 4.0