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Feb 7, 2019 at 9:11 vote accept Felipe Augusto de Figueiredo
Feb 7, 2019 at 7:18 comment added Carlo Beenakker ${\cal O}(M^{-7})$ means that the next order term in an expansion in powers of $1/M$ is of order $M^{-7}$; I used Mathematica for the integrals; it will not return an answer for a symbolic $M$, but it will for any integer $M$ and then the polynomial in the denominator is easily obtained; perhaps there is a way to obtain this directly, but to demonstrate the absence of independence of $z_1$ and $z_2$ this suffices.
Feb 6, 2019 at 22:48 comment added Felipe Augusto de Figueiredo One more question, how did you find $a^2\,\mathbb{E}[|z_1|^2|z_2|^2]=\frac{1}{4M(M+1)(M-1)(M-2)}$?
Feb 6, 2019 at 22:43 comment added Felipe Augusto de Figueiredo What do you mean by ${\cal O}(M^{-7})$?
Feb 6, 2019 at 16:38 history edited Carlo Beenakker CC BY-SA 4.0
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Feb 6, 2019 at 15:14 history edited Carlo Beenakker CC BY-SA 4.0
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Feb 6, 2019 at 15:09 history edited Carlo Beenakker CC BY-SA 4.0
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Feb 6, 2019 at 15:03 history edited Carlo Beenakker CC BY-SA 4.0
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Feb 6, 2019 at 12:42 history answered Carlo Beenakker CC BY-SA 4.0