Skip to main content

Timeline for Cohomology of constant sheaves

Current License: CC BY-SA 4.0

3 events
when toggle format what by license comment
Feb 6, 2019 at 4:37 comment added Marc Hoyois Since every $k$-scheme of finite type has a $k$-rational point, $Spec(k)$ has no nontrivial fppf covers, hence it has no cohomology.
Feb 6, 2019 at 4:00 review First posts
Feb 6, 2019 at 7:05
Feb 6, 2019 at 3:56 history asked user639648 CC BY-SA 4.0