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Oct 29, 2009 at 22:48 comment added Jonah Sinick I don't have any idea of how one would treat the case with analytic rank > 1 - maybe it's not reasonable to expect an analogous approach in this case. Still, this different way of computing Sha is interesting even in the rank 0 and 1 cases in light of the fact that most elliptic curves over Q seem to have analytic rank 0 or 1. It would be interesting to identify a large and natural family of projective varieties over Q with the property that Hilbert's 10th problem is decidable for this class. (This would be analogous to Gromov's discovery of hyperbolic groups in relation to the word problem.)
Oct 29, 2009 at 14:20 comment added Pete L. Clark Ah, I see what you are saying. Yes, if the full BSD is given to you, you have a different way to compute the order of Sha. In the case where the analytic rank is zero, this seems to have a priori bounded running time. But if the analytic rank is greater than 1, how are you going to compute it (rigorously) without computing the Mordell-Weil rank instead? Anyway, I am far from an expert in the algorithmic aspects here. I hope someone else will weigh in.
Oct 29, 2009 at 8:20 comment added Jonah Sinick Thanks for your response. What I had in mind in referring to an effective bound on Sha and an a priori bound on running time is the strong from of the Birch and Swinnerton-Dyer conjecture - for example, I have the impression that in the analytic rank zero case it's possible to compute the size of Sha by computing the central critical value of the L-function attached to the elliptic curve to high precision (with running time bounded a priori) using the fact that elliptic curves are modular. But maybe I'm just confused.
Oct 29, 2009 at 7:58 vote accept Jonah Sinick
Oct 29, 2009 at 7:26 history answered Pete L. Clark CC BY-SA 2.5