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Feb 6, 2019 at 20:59 comment added Chen @JasonStarr and Phil: Thank you for the comments. I was considering $M'$ as an $\mathcal{O}_X$-module.
Feb 5, 2019 at 14:50 comment added Jason Starr @PhilTosteson. I agree with you. As formulated, the OP seems to be asking whether $M'$, considered as an $\mathcal{O}_X$-module, is then flat when considered as an $\mathcal{O}_{X_D}$-module, and the answer to that question is "no". However, if the OP changes the $\mathcal{O}_{X_D}$-module structure as in my comment, then $M'$ is flat as an $\mathcal{O}_{X_D}$-module.
Feb 5, 2019 at 14:41 comment added Phil Tosteson As worded I think Chen is not asking for that, and so the answer is no.
Feb 5, 2019 at 13:20 comment added Jason Starr Your formulation is unclear. Is the action of $t$ on $M'$ intended to be the composition of the epimorphism $M'\to M$ and the monomorphism $M\to M'$?
Feb 5, 2019 at 11:39 history asked Chen CC BY-SA 4.0