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Feb 5, 2019 at 17:38 vote accept Jacksbabypig
Feb 4, 2019 at 22:54 comment added Denis Nardin @MikeMiller Aaand there was still a residue mistake (I assumed that the Sylow subgroup wouldn't be trivial). Fixed now :)
Feb 4, 2019 at 22:49 history edited Denis Nardin CC BY-SA 4.0
added 2 characters in body
Feb 4, 2019 at 22:48 comment added mme I thought your answer was fine as it was, I just wanted to add something for anybody passing by :) Some small points: there is a surviving $C_p$ somewhere. Because $S^1$ is a non-discrete space as well as a group, can I suggest writing $H^2(BS^1; \Bbb F_p)$ on the second-to-last displayed line (and maybe similarly for $BC_n$) to avoid confusion?
Feb 4, 2019 at 22:32 comment added Denis Nardin @MikeMiller Thanks! I was trying to avoid using the fiber sequence $C_p\to S^1\to S^1$ to give a more "algebraic" proof, but you're right, the argument flows much better if we embrace it.
Feb 4, 2019 at 22:32 history edited Denis Nardin CC BY-SA 4.0
Inserted simplification in the proof
Feb 4, 2019 at 17:50 comment added mme Everything is correct. Your argument can be streamlined by working with the LHSS for $\Bbb Z/n \to D_{2n} \to \Bbb Z/2$ directly instead of passing to a $p$-Sylow, then reducing to the case of $S^1$, which has an automorphism extending negation on $\Bbb Z/n$. The induced map of this automorphism (complex conjugation) on $S^1$ is complex conjugation on $\Bbb{CP}^\infty$, so $\sigma b = -b$.
Feb 4, 2019 at 17:27 history edited Denis Nardin CC BY-SA 4.0
added 3 characters in body
Feb 4, 2019 at 17:27 comment added Denis Nardin I am oscillating between being convinced that this answer is correct and being convinced that it is complete bunk. Right now I think it's correct and I've got to leave now, so I'll offer it to you clemence..
Feb 4, 2019 at 17:25 history undeleted Denis Nardin
Feb 4, 2019 at 17:13 history deleted Denis Nardin via Vote
Feb 4, 2019 at 17:07 history undeleted Denis Nardin
Feb 4, 2019 at 17:07 history edited Denis Nardin CC BY-SA 4.0
Removed erroneous argument using the Bockstein
Feb 4, 2019 at 16:14 history deleted Denis Nardin via Vote
Feb 4, 2019 at 15:43 history answered Denis Nardin CC BY-SA 4.0