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Jan 31, 2019 at 11:16 comment added Ron P Thanks! k=1, the function is $\sum x_i^2$ which has a unique minimum at (1/n,...,1/n). k=n, the function is constant 1. It might be true for k=2,3 as well, but I'm not sure.
Jan 30, 2019 at 18:59 history answered YZ22 CC BY-SA 4.0