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Jan 31, 2019 at 6:28 vote accept Dominic van der Zypen
Jan 31, 2019 at 5:13 history edited Martin Sleziak
added the (graph-colorings) tag
Jan 30, 2019 at 22:23 comment added Will Brian @RamirodelaVega: I did realize that -- I just thought that getting "control" over the structure of the dense subsets of a space (as in the paper) might allow you to control the value of $\chi$. It looks like my intuition was wrong, though -- +1 for the great answer you just posted.
Jan 30, 2019 at 22:14 comment added Ramiro de la Vega @WillBrian. Note that $\kappa$-resolvability is equivalent to $\chi(X)=\kappa$ only for $\kappa=2$ since the restrictions are not required to take all values, only to be non-constant.
Jan 30, 2019 at 22:12 answer added Ramiro de la Vega timeline score: 10
Jan 30, 2019 at 14:02 comment added Will Brian My guess would be that you could build examples using the methods of this paper: arxiv.org/pdf/math/0609090.pdf. I'm not familiar enough with those methods to say for sure -- but maybe it's a start.
Jan 30, 2019 at 11:57 history asked Dominic van der Zypen CC BY-SA 4.0