Timeline for Is this condition sufficient for a variety to be reversible?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Apr 25, 2019 at 11:01 | history | bounty ended | CommunityBot | ||
| S Apr 25, 2019 at 11:01 | history | notice removed | CommunityBot | ||
| Apr 25, 2019 at 7:26 | answer | added | Keith Kearnes | timeline score: 3 | |
| S Apr 17, 2019 at 9:46 | history | bounty started | Joseph Van Name | ||
| S Apr 17, 2019 at 9:46 | history | notice added | Joseph Van Name | Draw attention | |
| Jan 28, 2019 at 21:23 | comment | added | Joseph Van Name | If $G$ is a group that contains a non-normal subgroup $H$, then $G$ is not Hamitonian, but $G$ is still reversible and the variety of groups is reversible. Regularity is out of the question since the variety of all quandles is reversible but if $(X,*,*^{-1})$ is a quandle with more than 3 elements and $x*y=x*^{-1}y=y$ for all $x,y\in X$, then every equivalence relation on $(X,*,*^{-1})$ is a congruence on $(X,*,*^{-1})$. In fact, this means reversibility does not imply any non-trivial property characterized by Mal'cev conditions. | |
| Jan 28, 2019 at 16:41 | comment | added | Gerhard Paseman | Do your assumptions imply that the algebras are congruence regular or Hamiltonian? That might give you a leg up. Gerhard "Not After Hamilton The Rapper" Paseman, 2019.01.28. | |
| Jan 28, 2019 at 13:03 | history | asked | Joseph Van Name | CC BY-SA 4.0 |