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Jan 28, 2019 at 8:31 history closed Francois Ziegler
Wojowu
Steven Landsburg
Lee Mosher
Stefan Waldmann
Duplicate of Is there a sheaf theoretical characterization of a differentiable manifold?
Jan 28, 2019 at 3:57 comment added Deane Yang Normally, when we say simply “a manifold”, we don’t assume it to have any geometric structure on it. The sphere, purely as a manifold, has no specific geometric properties. However, the unit sphere in $\mathbb{R}^n$ does.
Jan 27, 2019 at 23:37 comment added Sheldon How is that not clear to you. I specifically asked for things like gaussian curvature, metric tensor etc..which surely isn't purely topological. PS geometrical and topological aspects of geometric objects are never completely independent..
Jan 27, 2019 at 22:51 comment added Deane Yang It's not clear, at least to me, whether you're asking about a way to define, without using coordinates or an embedding into Euclidean space, the topological structure of a smooth manifold or the geometric properties of a Riemannian manifold without using coordinates. A smooth manifold has no geometric properties, only topological ones. In particular, there is no concept of curvature on a manifold per se. However, if the manifold has a Riemannian metric or is emedded into Euclidean space, then the metric or embedding has geometric properties such as curvature.
Jan 27, 2019 at 22:24 history edited Sheldon CC BY-SA 4.0
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Jan 27, 2019 at 20:15 comment added Steven Landsburg Anything that involves a preferred class of geodesics is going to have a lot more structure than a differentiable manifold.
Jan 27, 2019 at 17:00 review Close votes
Jan 28, 2019 at 8:31
Jan 27, 2019 at 16:42 answer added Victor Petrov timeline score: 0
Jan 27, 2019 at 16:30 review First posts
Jan 27, 2019 at 16:58
Jan 27, 2019 at 16:29 comment added Wojowu math.stackexchange.com/q/2010035/127263
Jan 27, 2019 at 16:28 history asked Sheldon CC BY-SA 4.0