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Jan 26, 2019 at 16:59 comment added Marty No need to assume unitarity. Smooth reps of $SL_2(Z_p)$ are finite-dimensional and factor through $SL_2(Z / p^k Z)$ for some $k$. Branching from $G$ to $K$, these $k$'s are unbounded. For Shalika's thesis... I'd consult Nevins' papers for the reference.
Jan 26, 2019 at 12:38 comment added Florin Radulescu This is great stuff.For a better intuition, I wish I could see how exactly this goes in a more simple case, like spherical series. Could that be that in this case (if necessary assume unitarity) only reprsentations from finite quotients of PSL(2,Z) by modular subgroups? Is there a way to obtain Shalika's thesis?
Jan 26, 2019 at 7:46 vote accept Florin Radulescu
Jan 26, 2019 at 6:10 history answered Marty CC BY-SA 4.0