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Jan 23, 2019 at 7:57 comment added vidyarthi I think the above construction works for $n=7$ also
Jan 23, 2019 at 7:14 comment added vidyarthi great and thanks! But, now, this gives rise to another question. Whether we require $n$ to be a multiple of $42$(or $d(d+1)$) or anything lower is sufficient?
Jan 23, 2019 at 0:35 history answered Mike CC BY-SA 4.0