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Jan 22, 2019 at 11:29 comment added Gerry Myerson This sequence may be oeis.org/A126263
Jan 22, 2019 at 4:59 answer added kodlu timeline score: 3
Jan 22, 2019 at 4:10 comment added Michael Hardy Maybe this is a bit of a tangent, but is any purpose served by writing $\left( \prod_{p_i \, \in \, A_{n-1}} p_i \right) + 1$ instead of $\left( \prod_{p \, \in \, A_{n-1}} p \right) + 1 \text{ ?} \qquad$
Jan 22, 2019 at 4:06 history edited Michael Hardy CC BY-SA 4.0
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Jan 22, 2019 at 3:23 comment added Joe Silverman Why do you say that $A$ "clearly" does not contain all primes? I'm pretty sure that that is a long-standing open problem. Similarly if you adjoin to $A_{n-1}$ only the smallest prime dividing $x_n$, which is maybe more in the spirit of Euclid's original proof that there are infinitely many primes.
Jan 22, 2019 at 2:24 history edited Vik78 CC BY-SA 4.0
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S Jan 22, 2019 at 2:22 history suggested Amir Sagiv CC BY-SA 4.0
Latex and a little english
Jan 22, 2019 at 2:15 review Suggested edits
S Jan 22, 2019 at 2:22
Jan 22, 2019 at 1:45 review First posts
Jan 22, 2019 at 2:15
Jan 22, 2019 at 1:44 history asked Vik78 CC BY-SA 4.0