Timeline for Numbers that are the sum of 2 distinct nonzero squares in exactly 1 way
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jan 29, 2019 at 3:02 | comment | added | Konstantinos Kanakoglou | You are welcome Greggz. | |
Jan 24, 2019 at 3:42 | history | edited | Konstantinos Kanakoglou | CC BY-SA 4.0 |
added 248 characters in body
|
Jan 21, 2019 at 18:57 | comment | added | Greggz | Thank you so much for your work and dedication | |
Jan 21, 2019 at 18:57 | vote | accept | Greggz | ||
Jan 21, 2019 at 18:22 | history | edited | Konstantinos Kanakoglou | CC BY-SA 4.0 |
added 8 characters in body
|
Jan 21, 2019 at 18:13 | comment | added | Konstantinos Kanakoglou | I have edited the answer providing more details and some examples. | |
Jan 21, 2019 at 18:10 | history | edited | Konstantinos Kanakoglou | CC BY-SA 4.0 |
added 832 characters in body
|
Jan 21, 2019 at 15:33 | comment | added | Konstantinos Kanakoglou | @Greggz, when a number $p=4k+1$ i just mean that $p\equiv 1(\mod 4)$. Regarding your second question: If all $a_i$ are integers then $r'_2(n)=1$ is equivalent to either $B=b+1=1+1=2$ or $B=b+1=2+1=3$ and $a_0$: even. In the latter case we get: $r'_2(n)=\frac{1}{2}(B-(-1)^{a_0})=\frac{1}{2}(3-1)=1$. | |
Jan 21, 2019 at 9:21 | comment | added | Greggz | Also, in your last point between brackets, can you explain it trough an example ? My math syntax is really limited. Thank you so much | |
Jan 21, 2019 at 9:19 | comment | added | Greggz | Thanks for your answer, can you please explain to me how do I test if a number is 4k+1 | |
Jan 21, 2019 at 3:46 | history | edited | Konstantinos Kanakoglou | CC BY-SA 4.0 |
added 440 characters in body
|
Jan 21, 2019 at 3:19 | history | answered | Konstantinos Kanakoglou | CC BY-SA 4.0 |