Timeline for Six yolks in a bowl: Why not optimal circle packing?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 21, 2019 at 14:49 | comment | added | Janne Kokkala | @MatthiasUrlichs If you look at the images in the question, the size of the circle of optimal 6- and 7-packings are the same, so removing any circle from the optimal 7-packing creates another optimal 6-packing. And if you remove a circle not on the center, you can move the other circles around a bit. So the $d$ is equal for both cases. | |
| Jan 21, 2019 at 14:31 | vote | accept | Joseph O'Rourke | ||
| Jan 21, 2019 at 9:36 | comment | added | Wojowu | @MatthiasUrlichs Assuming perfect, rigid disks, the $d$ is the same. | |
| Jan 21, 2019 at 8:08 | comment | added | Matthias Urlichs | However, the $d$ in $6 V(d)$ is smaller than the one in $5 V(d)$. You need to show that the inequality still holds. | |
| Jan 20, 2019 at 22:58 | history | answered | Martin Hairer | CC BY-SA 4.0 |