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Nov 3, 2014 at 3:32 comment added Nate Eldredge @QuinnCulver: No, I don't think so. By my reading the number $.++1$ is in that interval and maps to 1.
Dec 26, 2011 at 15:53 comment added Quinn Culver Isn't Conway's function constantly zero on the interval $[.++,.+++]$ (using Wikipedia's notation)? So strictly speaking, the function's range isn't $\mathbb{R}$ on every open set
Dec 11, 2010 at 18:32 comment added gowers Actually, I take that back -- I still hadn't completely understood Conway's example.
Dec 11, 2010 at 18:26 comment added gowers But that applies equally to the examples based on limiting density.
Dec 11, 2010 at 17:01 comment added Aaron Meyerowitz @gowers The ease with which one can specify an explicit pre-image of any real in any target domain interval.
Dec 11, 2010 at 14:50 comment added gowers These comments make me feel a bit slow: what does Conway's function have over the simpler functions given in several of the answers below?
Jul 17, 2010 at 6:42 vote accept falagar
Jul 17, 2010 at 5:23 comment added Pedro Teixeira OK, I don't have anything to add here, other than to say that this was the coolest thing I learned today. Wow!
Jul 16, 2010 at 16:50 comment added Vectornaut Why does everything Conway does end up making me cry? ^_^ p.s. I think that function definitely belongs here: mathoverflow.net/questions/22189/…
Jul 16, 2010 at 11:06 comment added Willie Wong Wow, that is a fabulous example.
Jul 16, 2010 at 7:13 history answered Robin Chapman CC BY-SA 2.5