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Jan 18, 2019 at 14:13 history edited François Brunault CC BY-SA 4.0
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Jan 17, 2019 at 21:14 comment added Zhi-Wei Sun Thank you for your computation. Though $D(p)$ is not exactly equal to $h(p^*)$, it seems that $h(p^*)$ divides $D(p)$. Can you find an odd prime $p$ with $h(p^*)\nmid D(p)$?
Jan 17, 2019 at 16:55 history answered François Brunault CC BY-SA 4.0