Timeline for Sum of squared nearest-neighbor distances between points in a square
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Jan 24, 2019 at 0:47 | vote | accept | T. Amdeberhan | ||
| Jan 21, 2019 at 14:26 | comment | added | Iosif Pinelis | I have replaced the computer algebra argument for Subcase 7.1 by an elementary convexity argument. Now the entire proof is completely elementary. | |
| Jan 21, 2019 at 14:25 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 21, 2019 at 2:06 | comment | added | Iosif Pinelis | The proof is finally completely done. | |
| Jan 21, 2019 at 2:05 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 21:59 | comment | added | Iosif Pinelis | One (hopefully) comparatively small step remains to finish the proof. | |
| Jan 17, 2019 at 21:58 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 21:33 | comment | added | Iosif Pinelis | I have now added yet another case, which appears to be the most difficult one. | |
| Jan 17, 2019 at 21:32 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 3:42 | comment | added | user44191 | It might be useful to note that there's still one case left - when 3 are 1s. | |
| Jan 17, 2019 at 3:38 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 3:21 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 3:13 | comment | added | Iosif Pinelis | I have now considered more cases and simplified the proof, by introducing Lemma 1. | |
| Jan 17, 2019 at 3:12 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 17, 2019 at 2:04 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 16, 2019 at 19:42 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 16, 2019 at 19:35 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |