Timeline for Uniqueness of minimizers in a problem in the Calculus of Variations - Part II
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 19, 2019 at 23:28 | vote | accept | Y.B. | ||
| Jan 18, 2019 at 1:06 | answer | added | Michael Renardy | timeline score: 2 | |
| Jan 17, 2019 at 16:53 | comment | added | Y.B. | @PiotrHajlasz Uhuh that's right. I definitely need to revise Functional Analysis :-) Thanks, I am very satisfied now and your (and Mateusz K.'s) answers/comments have been very helpful to me. | |
| Jan 17, 2019 at 15:37 | comment | added | Piotr Hajlasz | @Y.B. Sure you can since $|x|+|y|$ is a norm. Take $A=\{(x,y):|x|+|y|\}\leq 1$. | |
| Jan 17, 2019 at 14:12 | comment | added | Y.B. | @MateuszKwaśnicki Thanks a lot for your comment and for your help. That example is the best counterexample I can think of and I thank you for that. The point is that I am not sure it is possible to realize $|x|+|y|$ as $f_A$ for a convex $A \subset \mathbb R^N$. Can you prove it? Which $A$ could we use?Thanks. | |
| Jan 17, 2019 at 13:12 | comment | added | Mateusz Kwaśnicki | When $f_A(x,y) = |x| + |y|$, isn't the example from my answer to part I a counterexample? | |
| Jan 17, 2019 at 2:06 | answer | added | Michael Renardy | timeline score: 5 | |
| Jan 16, 2019 at 17:53 | answer | added | Piotr Hajlasz | timeline score: 5 | |
| Jan 16, 2019 at 17:06 | history | asked | Y.B. | CC BY-SA 4.0 |